Question

vă rog frumos,rezolvati-mi si mie exercitiul incercuit adica 12. Imi trebuie pentru astazi urgentt va roogg.

Answer 1

$\displaystyle a)x-3,25= \frac{7}{4} \Rightarrow x- \frac{325}{100} = \frac{7}{4} \Rightarrow 100x-325=175 \Rightarrow \\ \\ \Rightarrow 100x=175+325 \Rightarrow 100x=500 \Rightarrow x= \frac{500}{100} \Rightarrow \boxed{x=5} \\ \\ b)2,35+x=3 \frac{1}{4} \Rightarrow \frac{235}{100} +x= \frac{13}{4} \Rightarrow 235+100x=325 \Rightarrow \\ \\ \Rightarrow 100x=325-235 \Rightarrow 100x=90 \Rightarrow x= \frac{90}{100} \Rightarrow \boxed{x= \frac{9}{10} }$

$\displaystyle c)3,2-x= \frac{6}{5} \Rightarrow \frac{32}{10} -x= \frac{6}{5} \Rightarrow 32-10x=12 \Rightarrow \\ \\ \Rightarrow -10x=12-32 \Rightarrow -10x=-20 \Rightarrow x= \frac{20}{10} \Rightarrow \boxed{x=2} \\ \\ d)2x+ \frac{1}{9} =2,(1) \Rightarrow 2x+ \frac{1}{9} =\frac{19}{9} \Rightarrow 18x+1=19 \Rightarrow \\ \\ \Rightarrow 18x=19-1 \Rightarrow 18x=18 \Rightarrow x= \frac{18}{18} \Rightarrow \boxed{x=1}$

$\displaystyle e)x+3,(2)= \frac{23}{6} \Rightarrow x+ \frac{29}{9} = \frac{23}{6} \Rightarrow 18x+58=69 \Rightarrow \\ \\ \Rightarrow 18x=69-58 \Rightarrow 18x=11 \Rightarrow \boxed{x= \frac{11}{18} } \\ \\ f) 3,(3)-x=3 \frac{1}{4} \Rightarrow \frac{30}{9} -x= \frac{13}{4} \Rightarrow 120-36x=117 \Rightarrow \\ \\ -36x=117-120 \Rightarrow -36x=-3 \Rightarrow x= \frac{3}{36} \Rightarrow \boxed{x= \frac{1}{12} }$

$\displaystyle g) \frac{11}{25} +x= \frac{6}{5} \Rightarrow 11+25x=30 \Rightarrow 25x=30-11 \Rightarrow \\ \\ \Rightarrow 25x=19 \Rightarrow \boxed{x= \frac{19}{25} } \\ \\ h)1,(2)-x= \frac{1}{2} \Rightarrow \frac{11}{9} -x= \frac{1}{2} \Rightarrow 22-18x=9 \Rightarrow -18x=9-22 \Rightarrow \\ \\ \Rightarrow -18x=-13 \Rightarrow \boxed{x= \frac{13}{18} }$