Question

va rog frumos sa imi explicati .

Answer 1

$2^{ x^{2} +x+0,5}=4 \sqrt{2} \\ 2^{ x^{2} +x+0,5}= 2^{2+ \frac{1}{2} } \\ x^{2} +x+0,5=2+0,5 \\ x^{2} +x-2=0 \\ delta=9 \\ x=-2;x=1$