Question

Va rog frumos sa ma ajutati​

Answer 1

13.A, O, B coliniare⇒m(∠AOD)+m(∠DOC)+m(∠BOC)=180°⇒3*m(∠DOC)+m(DOC)+m(∠DOC)=180°⇒5*m(∠DOC)=180°⇒m(∠DOC)=180:5=36°⇒m(∠AOD)=3*36°=108°

14. Notam m(∠AOB)=x, m(∠BOC)=y, m(∠COD)=z.

x+y+z=180°

x:y=2 rest 12⇒x = 2*y+12

z=y+16°

Deci 2y+12+y+y+16=180°⇒4y+28=180°⇒4y=152°⇒y=38°⇒x=2*38+12=88°⇒z=38+16=54°

Asadar m(∠AOB)=88°, m(∠BOC)=38°, m(COD)=54°