Question

Va rog frumos sa ma ajutati cu ex. 7.

Answer 1

³²₁₆S  ; ³³₁₆S   ; ³⁴₁₆S   ; ³⁶₁₆S

a) (A1*C1+A2*C2+A3*C3+A4*C4)/100 = 32*0,9502+33*0,0075+34*0,0421+0,0002*36 = 32,0925

b) 32g S (1 mol) .......................6,022*10^23 atomi
xg S...........................................903300*10^23 

x = (32*903300*)/6,022 = 4800000g = 4800 kg S = 4,8 tone S