Question

Va rog frumos sa ma ajutati cu un exercitiu :
a) [ (1,(3 ), - 1 supra 3 la puterea 2 : 0,5 la puterea 2 )] :3 +0,(6):0.12 ]

b) [19 supra 6+(1 +1supra3 la puterea 9 :(1,(3)la puterea 8 ] * 0.02 la puterea 3

c) [(2 supra 3 la puterea 2 * 0,(6) la puterea 3 ] :4 supra 9 la uterea 5

AM NEVOIE URGENT !!!!!!!!

Answer 1

a) [ (1,(3 ) - ( 1/ 3)² : (0,5)² )] :3 +0,(6):0.12 ] 
1,(3)=(13-1)/9=12/9 simplif.cu 3=4/3
0,(6)=6/9 simplif.cu 3=2/3
[4/3-(1/9):0,25]:3+2/3:12/100=
[4/3-1/9:25/100]:3+2/3·100/12=
[4/3-1/9·100/25];3+50/9=
[4/3-4/9]:3+50/9=
(12-4)/9:3+50/9=
8/9·1/3+50/9=
8/27+50/9=(8+150)/27=158/27

b) [19/6+(1 +1/3⁹ :(1,(3)⁸ ] x0.02³=
1,(3)=12/9=2/3
[19/6+(1+3⁻⁹:2⁸/3⁸)]x8/1000000=
[19/6+(1+3⁻⁹x3⁸:2⁸)]x2³:10⁶=
[19/6+(1+3⁻⁹⁺⁸:2⁸)]x2³:(2x5)⁶=
[19/6+(1+3/256)]x2³:(2⁶x5⁶)=
[19/6+259/256]x2³⁻⁶x5⁶=
[(128x19+259)/768]x2⁻³x5⁶=
2691/768x5⁶/2³=
2691/768x15625/8=(2691+15625x96)/768=1502691/768=1956intreg 483/768