Question

va rog frumos sa mă ajutati la exercițiile 10si11

Answer 1

10
a) 125×1111³- 5555³= 125×1111³- 5³×1111³=1111³×(125-125)= 0

b) 9⁵ - (3⁵)²+8⁴ -(2⁴)³= 3¹⁰ - 3¹⁰+ 2¹² - 2¹²= 0+0=0

c) 2⁷÷4³+ 3³×27÷3⁵+(3¹×2⁴- 4²)÷2³=2⁷÷2⁶+ 3³×3³÷3⁵+(3¹×2⁴- 2⁴)÷2³=

=2+ 3+2⁴×(3- 1)÷2³=5+4=9

11.
a= Claudiu
b= Cristina

a+b=41
a-10= (b-10)/2
2a-20=b-10
2a-b=20-10
2a-b=10
b=2a-10

a) a+b=41
a+2a-10=41
3a=41+10
3a=51
a=17
b=34-10
b=24

17+24=41

b)24-17=7
2/3=14/21
17-3=24-3
in urma cu 3 ani