Question

Va rog frumos sa ma ajutati ! macar cat stiti .
Dau coroana+20 pct!

Answer 1

2)

i) $\it(\sqrt5)^4 = [(\sqrt5)^2]^2=5^2=25$

j) $\it (0,3)^3 = 0,3\cdot0,3\cdot0,3 =0,27$ 

$\it\ 3e)\ \ \left(\dfrac{2}{5}\right)^{-4} = \left[\left(\dfrac{2}{5}\right)^{-1}\right]^4 =\left(\dfrac{5}{2}\right)^4 =\dfrac{5^4}{2^4} = \dfrac{625}{16}$

[tex]\it 2r)\ \sqrt7(\sqrt7)^5 =(\sqrt7)^{1+5} =(\sqrt7)^6 =[(\sqrt7)^2]^3 =7^3=343 \\ \\ s)\ (-3)^{-2} = \dfrac{1}{(-3)^2} =\dfrac{1}{9}[/tex]



 

Answer 2

Am facut ex.2 deocamdata , acum ai si 3 si 4