Question

Va rog frumos sa ma ajutati si pe mn...rezolvati va rog problema asta

Answer 1

$\boxed{A_t = A_l + 2 \cdot A_b}\\ \\ A_l = P_b \cdot h = 4 \cdot 6 \cdot 9 = 216~cm^2 \\ \text{Cum facem aria bazei ?} \\ \to \text{1.Folosim formula asta} \to \boxed{\dfrac{3l^2\sqrt3}{2}} \\ \\ \to \text{sau} \\ \\ \to \text{2.Folosim aria }\Delta AOB \text{ care este echilateral si imultim cu 6.} \to \boxed{6\cdot \dfrac{l^2\sqrt3}{4}} \\ \\ A_b = 6\cdot \dfrac{4^2\sqrt3}{4} =24 \sqrt3 \\ \\ A_t = A_l + 2 \cdot A_b \\ A_t = 216 + 2 \cdot 24\sqrt3 \\ \boxed{A_t = \boxed{216 + 48\sqrt3~cm^2}}$