Question

va rog frumos sa-mi rezolvati problema

Answer 1

RQ=QF=AF=AR = 4 dam

S RQFA = RQ² ⇒S RQFA =4² ⇒ S RQFA = 16 dam²

SΔARB = (AR·RB)/2 ⇒ SΔARB = (4·2)/2 ⇒SΔARB = 4 dam²

SΔAFC = (AF·CF)/2 ⇒SΔAFC = (4·2)/2 ⇒SΔAFC = 4 dam²

SΔBQC = (BQ·QC)/2 ⇒ SΔBQC = 2·2/2 ⇒SΔBQC = 2dam²

Suprafata acoperita de gazon = SΔARB +SΔAFC+SΔBQC ⇒
Suprafata acoperita de gazon= (4+4+2)dam² = 10 dam²

Suprafata acoperita de flori = S RQFA - Suprafata acoperita de gazon ⇒

Suprafata acoperita de flori = (16-10)dam² = 6dam²

Suprafata acoperita de flori ∠ Suprafata acoperita de gazon

AB² = RB² + AR² ⇒AB²=2²+4² ⇒AB=√20 ⇒AB=2√5=AC
BC²=BQ²+QC² ⇒BC² = 2²+2² ⇒BC=2√2
PΔABC = 2√5+2√5+2√2 = 4√5+2√2

2∠√5∠3
1∠√2∠2⇒ PΔABC ∠12