Question

va rog îl vreau pe 25

Answer 1

| x² - 1 | = | ( x + 1 ) ( x - 1 ) |

⇔ | x² - 1 | + | x + 1 | ≤ | x - 1 | + 1

Daca x > 0

| x² - 1 | + x ≤ | x - 1 |

Daca x ∈ R

√( x² - 1)² - √(x-1)² + √(x+1) ≤ 1

(x - 1) · ( x+1) - x+1 + x + 1 ≤ 1

(x - 1) · (x+1) ≤ -1

x-1 = 1

x = 2

x - 1 = -1

x = 0

x+1 = 1

x = 0

x+1 = -1

x = -2

- 2 ≤ x ≤ 0

x ∈ [ -2 ; 0 ]