Question

Va rog îmi trebe urgent pe mâine cine ma poate ajuta ​

Answer 1

1. (1/2+1)·$\sqrt{3}$ (aducem la acelasi numitor in paranteza)=$\frac{3}{2}$·$\sqrt{3}$=$\frac{3\sqrt{3} }{2}$

2. $\frac{\sqrt{3} }{2}$·$\frac{\sqrt{3} }{3}$-$\frac{1}{2}$=$\frac{3}{6} - \frac{1}{2}= \frac{1}{2} - \frac{1}{2}= 0$

3. $\frac{\sqrt{2} }{2}$·$\frac{\sqrt{2} }{2}$+$\frac{1}{2}$=$\frac{2}{4} + \frac{1}{2} = \frac{1}{2} + \frac{1}{2}= \frac{2}{2}= 1$

4. ($\frac{\sqrt{3} }{2}$)²-($\frac{\sqrt{2} }{2}$)²=$\frac{3}{4} - \frac{2}{4} = \frac{1}{4}$

5. tgx·ctgx=1 ⇒ tg80·ctg80-1= 1-1= 0

6. (1+1):$\frac{1}{2}$= 2·2=4