Question

va rog îmi trebu urgent ​

Answer 1

Explicație pas cu pas:

$log_{3}x = \dfrac{1}{2} log_{3}36 - \dfrac{1}{3}log_{3}8 + 2log_{3}5$

$log_{3}x = log_{3} \sqrt{36} - log_{3} \sqrt[3]{8} + log_{3} {5}^{2}$

$log_{3}x = log_{3}6 - log_{3}2 + log_{3}25$

$log_{3}x = log_{3} \dfrac{6 \cdot 25}{2} \iff log_{3}x = log_{3}75 \\</p><p>\implies x = 75$