Question

Va rog...in imagine :*

Answer 1

f(x)=(5-x)/2
5-x=0
-x=-5       inmultim -1
x=5

g(x)=5x+1
5x+1=0
x=-1/5
a) F(0)=(5-0)/2=5/2
f(0)=5/2
g(0)=5·0+1=1
g(0)=1

f(x)≥g(x)

f(1)=2     g(1)=6
f(2)=3/2     g(2)=11
f(-1)=3      g(-1)=-4
f(-2)=7/2    g(-2)=-9

pt.x∈(-α, 0]  f(x)>g(x)
pt.x∈(1,+α), f(x)<g(x)
g(x) nu este niciodata egal cu g(x)