Question

VA ROG MA AJUTATI ....multumesc
prob 3,4,5,6,
+

Answer 1

3.AD=√(√2x2√2)=√(2x2)=2 cm
BC=√2+2√2=3√2 cm
A=3√2x2/2=3√2 cm²

4.  2²=4
    4²=16
(2√5)²=20
observam ca 2²+4²=(2√5)²    rezulta ca triunghiul este dreptunghic

5.PN=√(10²-8²)=√(100-64)=√36=6 cm
AΔMNP =6x8/2=24 cm²
ducem inaltimea NA_I_MN
AΔMNP = NAxMP/2
24=NAx10/2
NA=24x2/10=4,8 cm
Pdreptunghiului=(8+6)x2=28 cm

6.BD²=25²-AD²
BD²=30²-(25-AD)²
25²-AD²=30²-(25-AD)²
25²-AD²=30²-625+50AD-AD²
50AD=350
AD=7 cm
DC=25-7=18 cm
BD=√(25²-7²)=√(625-49)=√576=24 cm
AΔABC=BDxAC/2=24x25/2=12x25=300 cm²
PΔABD=25+24+7=56 cm