Question

va rog . metoda mersului invers

Answer 1

3.a)
(3a+5)x5 - 3 = 292
5(3a+5) = 292+3 = 295 si simplificam prin 5
3a+5 = 59
3a= 59-5 = 54
a = 54 : 3 = 18

b)
(c-17)x3  + 15 = 45
3(c-17) = 45-15 = 30, simplificam prin 3
c-17 = 10
c= 10+17 = 27
=========================
Succes in continuare!