Question

Va rog mult!!!!!!!!!!!! Aflati masurile unghiurilor unui triunghi stiind ca acestea sunt invers propotionale cu numerele:0,5;0,2;0,125

Answer 1

(a,b,c) ip (0,5;0,2,0,125)==a+b+c=180(=)0,5k+0,2k+0,125k=180(=)5/10+2/10+125/1000=180(=)7/10+125/1000=180(=)132/1010k=180/1(=)132/101k=18/1==132/101x18/1(=)2214/101k=)k=21,92
a/0,5=b/0,2=c/0,125=K
a/0,5=k=)a=0,5k(=)a=22,42
b/0,2=K=)b=0,2k(=)b=22,12
c/0,125=k=)c=0,125k(=)c=22,045