Question

va rog mult, ajuta.ti.maaa

Answer 1

1) b),n)

CaHbOcNdXe

NE = [(2a+2)-(b-d+e)]/2 = [(2*4+2)-10]/2 = 0

%O = 64/122*100 = 26,22

2) c),s)

F,M = C4H6O2

NE = (2*4+2-6)/2 = 2 

%O = 32/118*100 = 27,11

F.g = CnH2n-2O2

3) a),m), 

F.M = C13H12O

NE = (2*13+2-12)/2 = 8

%O = 16/184*100 = 8,69

F.g = CnH2n-6O

4) d), o)

F.M => C6H12O 

F.g: CnH2nO

NE = (2*6+2-12)/2 = 1

%O = 16/100*100 = 16

5) d),p)

F.M => C18H38O

F.g: CnH2n+2O

NE = 0

%O = 16/270*100 = 5,92