Question

va rog mult ajutorecuati ex [2x]=x+4;[x²+2]=x-3 ;[[x+1]²]=x+2 ;[3x]=x+4 ;[4x]=[x+1]² ;

Answer 1

a)(x+4)² +(x-2)² -2x²=X²+8x+16+x²-4x+4-2x²=2x²-2x²+8x-4x+16+4=4x+20 b)(2x-3)²-(3x+5)²+(2x+5)(2x-5)=4x²-12x+9-9x²-30x-25+4x²-25= -x²-42x+41 c)(x+5)²-(x-2)(x+2)+2(x+1)²=x²+10x+25-x²+4+2(x²+2x+1)=10x+29+2x²+4x+2=2x²+14x+31 d)(3+4x)²+4(x-2)²-(x+3)(x-3)=9+24x+16x²+4(x²-4x+4)- x²+9=16x²+4x²-x²+24x-16x+16+9=19x²+8x+25