Question

va rog mult ajutorrrr descompuneti in factori.
(x+1)totul la puterea 3-(x-2)totul la puterea 3
(y-3)totul la puterea3+(y+1)totul la puterea 3 va rog mult

Answer 1

formulele sunt  a³-b³=(a-b)(a²+ab+b²)
                         a³+b³=(a+b)(a²-ab+b²)

(x+1)³-(x-2)³=(x+1-x+2)[(x+1)²+(x+1)(x-2)+(x-2)²=
=3(x²+2x+1+x²+x-2x-2+x²-2x+4)=
=3(3x²-x+3)

(y-3)³+(y+1)³=(y-3+y+1)[(y-3)²-(y-3)(y+1)+(y+1)²=
=(2y-2)(y²-6y+9-y²+3y+y+3+y²+2y+1)=
=2(y-1)(y²+13)