Question

va rog mult am evaluare​

Answer 1

Răspuns:

3. (2x+1) *(2-x)/ (x+2)(2-x)  = (4x-2$x^{2}$+2 - x)/(2x-$x^{2}$-2x+4)= $\frac{3x-x^{2}+2 }{-x^{2} +4}$

4. a) $\frac{6xy}{9x^{2} } = \frac{2y}{3x}$

b) $\frac{x+3}{5x+15} = \frac{x+3}{5(x+3)}$= $\frac{1}{5}$

c) $\frac{x^{2}-4x+4 }{x^{2}-2x} = \frac{(x-2)(x-2)}{x(x-2)}$= $\frac{x-2}{x}$