Question

Va rog mult cu rezolvare ; " * " inseamna inmultire
$(\frac{3x^{2} }{2y^{5} })^{2}} : (\frac{-2x}{3y} )^{-3} * (\frac{4x}{-6yx^{2} } )^{-2}}$

Answer 1

Răspuns

Explicație pas cu pas:

$(\frac{3x^{2} }{2y^{5} })^{2}} : (\frac{-2x}{3y} )^{-3}*(\frac{4x}{-6yx^{2} } )^{-2}}=(\frac{9x^4}{4y^{10}}):(\frac{27y^3}{-8x^3})*(\frac{36y^2x^4}{16x^2})=(\frac{9x^4}{4y^{10}})*(\frac{-8x^3}{27y^3})*(\frac{36y^2x^4}{16x^2})=\frac{-9*8*36*x^{11}*y^2}{4*27*16*x^2y^{13}}=\frac{-3x^9}{2y^{11}}$