Question

va rog mult dau 15 pcte​

Answer 1

a)

$(1 + a + b) {}^{2} = 1 {}^{2} + a {}^{2} + b {}^{2} + 2 \times 1a + 2 \times 1b + 2ab = 1 + a {}^{2} + b {}^{2} + 2a + 2b + 2ab$

b)

$(2x + y + z) {}^{2} = (2x {)}^{2} + y {}^{2} + z {}^{2} + 2 \times 2xy + 2 \times xz + 2yz = 4x {}^{2} + y {}^{2} + z {}^{2} + 4xy + 4xz + 2yz$

c)

$(5 + 4a + 3b) {}^{2} = 5 {}^{2} + (4a) {}^{2} + (3b) {}^{2} + 2 \times 5 \times 4a + 2 \times 5 \times 3b + 2 \times 4a \times 3b = 25 + 16a {}^{2} + 9b {}^{2} + 40a + 30b + 24ab$

Sper ca intelegi!

☆Mult succes!!☆

Answer 2

Răspuns:

1+a²+b²+2a+2b+2ab ;   b)   25+16a²+9b²+40a+30b+24ab ;                                        c)    4x²+y²+z²=4xy+4xz+2yz

Explicație pas cu pas: