Question

va rog mult ... dau coroana...​

Answer 1

Răspuns:

c(a+2)= 8(b+3)  =>   (a+2)= $\frac{8(b+3)}{c}$   => c= $\frac{8(b+3)}{a+2}$

c*10=(b+3) (c+4)   => (b+3)= $\frac{10*c}{c+4}$

(a+2)*(c+4)= 80     => (a+2) = $\frac{80}{c+4}$  =>   c+4 = $\frac{80}{a+2}$

a= $\frac{80}{c+4}$ - 2 = $\frac{80- 2c -8}{(c+4)}$= $\frac{72-2c}{c+4}$

b= $\frac{10*c}{c+4}$ -3= $\frac{10c-3c-12}{c+4}$ = $\frac{7*c-12}{c+4}$

c= $\frac{8*10*c}{(c+4)}$ * $\frac{(c+4)}{80}$ =$\frac{80c}{80}$   c=1

1+4= 80:(a+2)  a+2= 80:5         a= 16-2= 14   a= 14

b+3= 10: 5=2   b= 2-3=-1     b= -1

verif 14+2:8= 16:8= 2

-1+3:1= 2      

10: 1+4= 10:5= 2