Question

Va rog mult dau coroana!​

Answer 1

$\it Frac\c{\it t}ia\ se\ scrie:\\ \\ \dfrac{2+2\cdot\dfrac{2^{2013}-1}{2-1}}{(2^2)^{1008}}=\dfrac{2+2(2^{2013}-1)}{2^{2016}}=\dfrac{2+2^{2014}-2}{2^{2016}}=\dfrac{2^{2014}}{2^{2016}}=\dfrac{1}{4}$

Answer 2

Răspuns:

Explicație pas cu pas: