Question

Va rog mult! dau coroană! ! Sa fie mica.ex 18.Va roog

Answer 1

1nr. /------/ 2nr. /------/+2 3nr./------/+4 4nr. /------/+6 =740
1) 2+4+6=12 (S)-surplusurilor;
2) 1×4=4 (S)-p. egale;
3) 740-12=728 (S)-fara surplus;
4) 728:4=182-1nr.;
5) 182+2=184-2nr.;
6) 182+4=186-3nr;
7) 182+6=188-4nr;

Suma a patru nr. consecutive impare este de 78. Afla nr.
1nr. /------/ 2nr./------/+1 3nr./------/+2 4nr/------/+3 =78
1) 1+2+3=6 (S)-surplusurilor;
2) 1×4=4 (S)-p. egale;
3) 78-6=72 (S)-fara surplus;
4) 72:4=18-1nr.;
5) 18+1=19-2nr.;
6) 18+2=20-3nr;
7) 18+3=21-4nr.;

Answer 2

a+b+c+d=740
b=a+2
c=a+4
d=a+6

a+a+2+a+4+a+6=740
4a+12=740
4a=740-12
4a=728
a=728:4
a=182
b=182+2=184
c=182+4=186
d=182+6=188

182+184+186+188=740

Problema:
Suma a patru numere impare consecutive este 728.Afla numerele.

a+b+c+d=728
a+a+2+a+4+a+6=728
4a+12=728
4a=728-12
4a=716
a=716:4
a=179
b=179+2=181
c=179+4=183
d=179+6=185

179+181+183+185=728