Question

va rog mult ex 10 a si b​

Answer 1

Răspuns:

Explicație pas cu pas:

a) (a/3-3/a)·a²/(a²-9)+(6-a)/3=[(a·a-3·3)/3·a]·a²/(a²-9)+(6-a)/3=[(a²-9)/3·a]·a²/(a²-9)+(6-a)/3=a/3+(6-a)/3=(a+6-a)/3=6/3=2

b) [1/(a-1)-2/(a-2)]·[(a-3)²-1]/a=[(a-2)-2(a-1)/(a-1)(a-2)]·[(a-3-1)(a-3+1)/a]=

[(a-2-2a+2)/(a-1)(a-2)]·[(a-4)(a-2)/a]=[-a/(a-1)(a-2)]·[(a-4)(a-2)/a]=

[-a/(a-1)]·[(a-4)/a]=[-1/(a-1)]·(a-4)=[-1/-(1-a)]·(a-4)=[1/(1-a)]·(a-4)=(a-4)/(1-a)