Question

va rog mult ex 19 punctul a,multumesc

Answer 1

[tex]a)\frac{4-3\sqrt6}{2\sqrt3}-\frac{5\sqrt6-7}{4\sqrt2}+\frac{3+2\sqrt6}{5\sqrt3}-\frac{4\sqrt6-3}{6\sqrt2}=\\ \frac{4\sqrt3-9\sqrt2}{6}-\frac{10\sqrt3-7\sqrt2}{8}+\frac{3\sqrt3+6\sqrt2}{15}-\frac{8\sqrt3-3\sqrt2}{12}=\\ \frac{16\sqrt3-36\sqrt2-30\sqrt3+21\sqrt2}{24}+\frac{12\sqrt3+24\sqrt2-40\sqrt3+15\sqrt2}{60}=\\ \frac{-14\sqrt3-15\sqrt2}{24}+\frac{-28\sqrt3+39\sqrt2}{60}=\\ \frac{-70\sqrt3-75\sqrt{2}-56\sqrt3+78\sqrt2}{120}=\\ \frac{3\sqrt2-126\sqrt3}{120}=\frac{\sqrt2-42\sqrt3}{40}[/tex]