Question

Va rog mult help la 5 va mulțumesc mult

Answer 1

[tex]\it \dfrac{a}{b} =3-\sqrt5 \\\;\\\; \dfrac{a^2+b^2}{ab} =\dfrac{a^2}{ab} + \dfrac{b^2}{ab} = \dfrac{a}{b} + \dfrac{b}{a} = 3-\sqrt5 +\dfrac{1}{3-\sqrt5} = \\\;\\ \\\;\\ =3-\sqrt5+\dfrac{3+\sqrt5}{4} = \dfrac{12-4\sqrt5+3+\sqrt5}{4} =\dfrac{15-3\sqrt5}{4} [/tex]