Question

Va rog mult mult mult mult de tot!!!!!

Answer 1

MAl2O3=2AAl+3AO=2*27+3*16=54+48=102g/mol

Raport atomic ==> Al2O3=2:3

Raport de masa = Al2O3=54g/48g=9g/8g

Substanta Al2O3 se numeste oxid de aluminiu (Al2O3)

%Al=mAl/M*100=54/102*100=52.941%

%O=mO/M*100=48/102*100=47%

masa oxidului de aluminiu din 2 moli ==> n=m/M==>m=n*M=2*102=204g Al2O3

In 102g Al2O3 se gasesc 48g O2
x=204g..................................96gO2

n=m/M=204/102=2 moli Al2O3