Question

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Answer 1

$\it a)\ \ (12,\ \ 16,\ \ 20)\ -\ triplet\ \ pitagoreic\ \Rightarrow AC=16\ cm\\ \\ b)\ \mathcal{A}=\dfrac{c_1\cdot c_2}{2}=\dfrac{12\cdot16}{2}=12\cdot8=96\ cm^2\\ \\ \\ c)\ \ AM=\dfrac{BC}{2}=\dfrac{20}{2}=10\ cm$