Question

va rog mult problema 3 urgent

Answer 1

2KClO3 -> 2KCl + 3 O2
a) V O2 = 4*3*22.4/2=134.4 L
b) m KCl = 74.5*4=298 g (md)
ms = md + mH2O
V h2o = m h2o ( densitatea = 1g/mL )
=> ms = 298 + 302 = 600 g
c = 298*100/600 = 49.66%
c) 2H2O2 -> H2O + O2 ( catalizator MnO2)
n H2O2 = 134.4*2/22.4 = 12 mol