Question

Va rog mult sa ma ajutati ​

Answer 1

Răspuns:

Explicație pas cu pas:

vom face transformarile separat, dupa ce, le vom inlocui in expresie

$2,1(3)=\frac{213-21}{90}=\frac{192}{90}\\1,(6)=\frac{16-1}{9}=\frac{15}{9}\\\frac{2,1(3)}{1,(6)}= \frac{192}{90}:\frac{15}{9}=\frac{192}{90}*\frac{9}{15} =\frac{64}{10}*\frac{1}{5} =\frac{64}{25*2}\\\sqrt{\frac{2,1(3)}{1,(6)}}=\sqrt{\frac{64}{25*2}}=\frac{8}{5\sqrt{2} }\\\\\sqrt{\frac{2,1(3)}{1,(6)}}-\frac{3}{\sqrt{2} }= \frac{8}{5\sqrt{2} }-\frac{3}{\sqrt{2} }=\frac{8-15}{5\sqrt{2} } =\frac{-7}{5\sqrt{2} }\\(\sqrt{\frac{2,1(3)}{1,(6)}}-\frac{3}{\sqrt{2} }):1,4=[tex]=\frac{-7}{5\sqrt{2} }*\frac{10}{14}=-\frac{1}{\sqrt{2} }$:\frac{14}{10}=[/tex]

$[-\frac{1}{\sqrt{2} } ]^{3}=-\frac{1^{3}}{(\sqrt{2})^{3}}=-\frac{1}{(\sqrt{2})^{2}*\sqrt{2}}=-\frac{1}{2\sqrt{2} }=-\frac{1*\sqrt{2}}{2*(\sqrt{2})^{2}} =-\frac{\sqrt{2}}{2*2}=-\frac{\sqrt{2} }{4}.$