Question

va rog mult sa mă ajutați,dau coroana​

Answer 1

Doar cu atât te pot ajuta...乁( •_• )ㄏ

Answer 2

$a)\, (-72x^2+48x^4-36x^3):(-4x^2)=$

   $\frac{-72x^2+48x^4-36x^3}{-4x^2} =\frac{4x^2\cdot(-18+12x^2-9x)}{-4x^2}^{(-4}$

  $= \frac{-x^2\cdot (-18+12x^2-9x)}{x^2} ^{x^2)}=-(-18+12x^2-9x)$

  $\implies 18-12x^2+9x=-12x^2+9x+18$

$b)\, \sqrt{3} \,(2\sqrt{3} -x)+\sqrt{6} \,(3\sqrt{2}\, x+\sqrt{3} )=$

   $6-\sqrt{3} \,x+\sqrt{6} \,(3\sqrt{2} \,x+\sqrt{3} )=$

   $6-\sqrt{3} \,x+3\sqrt{12} \,x+\sqrt{18} =$

   $6-\sqrt{3} \,x + 3\cdot2\sqrt{3} \,x+3\sqrt{2} =$

   $6-\sqrt{3} \,x+6\sqrt{3} \,x+3\sqrt{2} =6+5\sqrt{3} x+3\sqrt{2}$

$c)\,(21x^3-14x^2):(-7x^2)+(x-1)(x+2)=$

   $\frac{21x^3-14x^2}{-7x^2} +x^2+2x-x-2=$

   $\frac{7x^2(3x-2)}{-7x^2}^{(-7x^2} +x^2+2x-x-2=$

  $-(3x-2)+x^2+2x-x-2=$

  $-3x+2+x^2+x-2=-3x+x^2+x=-2x+x^2$

________________________________________________________

$x^{m+1}+x^m+x^{m-1}=$

$x^{m-1}(x^{m+1-(m-1)}+x^{m-(m-1)}+x^{x-1-(m-1)})=$

$x^{m-1}(m^{m+1-m+1}+x^{m-m+1}+x^{m-1-m+1})=$

$x^{m-1}(x^{1+1}+x^1+x^0)\implies = x^{m-1}(x^2+x+1)$

________________

$x^{2014}-x^{2013}-x^{2012}=$

$x^{2012}\cdot x^2 -x^{2012}\cdot x^1 - x^{2012}\cdot x^0=$

$x^{2012}(x^2-x^1-x^0) \implies x^{2012}(x^2-x-1)$

__________________________________________________________

$(2x+3)^2+(2x-3)^2\implies folosind\:formula\: (a+b)^2=a^2+2ab+b^2$

$\implies (2x+3)^2=(2x)^2+2\cdot2x\cdot3+3^2=4x^2+12x+9$

$\implies (2x-3)^2=(2x)^2-2\cdot2x\cdot3+3^2=4x^2-12x+9$

$(2x+3)^2+(2x-3)^2=4x^2+12x+9+4x^2-12x+9$

$\implies 4x^2+9+4x^2+9=8x^2+18$

__________________________________________________________

$11^2+121b^2+22c^2= 11^2+11^2b^2+2 \cdot 11c^2$

$\implies = 11(11+11b^2+2c^2)$

_____________

$ab^2+a^2b+ab=ab\,(b+a+1)$

_____________

$x^{2015}+x^{2014}+x^{2013}=x^{2013}\cdot x^2+2^{2013}\cdot x^1 + x^{2013}\cdot x^0$

$\implies = x^{2013}(x^2+x+1)$

_____________

$2015\,x^{2017}+2015\,x^{2016}=2015\,x^{2016}(x-1)$