Matematică, întrebare adresată de cosmidudu, 9 ani în urmă

Va rog mult sa ma ajutati repede

1) [(2^10)^8+6^5x3^7+2^3^2]:[(2^5)^16+6^12:2^7+2^9]=
2) 10^2x[4+5x3^2-2^5+4^3x(4^9-3^2):12^3=
3) [(2^6)^4:2^3x(2^6+2^6)-4^6:2^10]:(2^28-2^2)+9=
4) X=8^33:[4^32x2^34+(2^5x2^20)^5:(16x2^23)+(7^5:7^5-1)^32x4]
5) Y=[(11-0^11)x(3^3-3^2)+1^2000]x(3^2-2^3)-3^2x2
6) (2+2x3)x{2x2^2x2^43-2^46+[3^148:3^43-(3^5)^21]+16}=
7) 122+12x{183:[(2x3^2x5^3)^4:(2^4x3^7x5^12)+(2^8)^9:2^72-1^27x5^0]-9x(54-2^4x3)}=
8) (5^17x5^18+7^23:7^15):(7x7^2x7^5+5^50:5^15)=
9) (10^3-125x2^3):123^123=
10) [(10^3:5^2:8+3^2x5^2):3^0]x2^20=
11) {[(12^2+5^2):13]^2-2^7-2^0}:2^3=

Răspunsuri la întrebare

Răspuns de wwwvoicuflori
6
sa incercam;
[(2^10)^8+6^5x3^7+(2^3)^2]:[(2^16+6^12:2^7+2^9]=
[(2^10x8+6^5x3^7+2^3x2)]:(2^5x16+6^12:2^7+2^9)=
(2^80+6^5x3^7+2^6):(2^80+6^12:2^7+2^9)=
(2^80+2^6+6^5x3^7):(2^80+2^7+2^9x6^12)=
(2^86+6^5x3^7):(2^96x6^12)=
(2^86+2^96):(6^5x6^12):3^7=
2^182:6^17:3^12
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