Question

va rog mult, urgent!!!!!!!
determinati masa mgo necesara pentru a interactiona cu 0.1 mol h2so4​

Answer 1

Răspuns:

MH2SO4 =2×1+32+4×16=98g/mol

MMgO =24+16=40g/mol

n=m/M

m=nxM=0,1×98=9,8g H2SO4

40g........98g

MgO + H2SO4 => MgSO4 + H2O

xg............9,8g

x=40×9,8/98=4g MgO

calculam in moli

1mol.........1mol

MgO + H2SO4 => MgSO4 + H2O

ymoli........0,1moli

y=1×0,1/1=0,1 moli MgO