Question

va rog muuult repede
Prin rationalizare

Answer 1

4.
a)(√54-12/2√6)+(48/√6-30/4√6-2/√24) =
=(3√6-12√6/12)+(48√6/6-15√6/12-2√6/12) =
=3√6-√6+8√6-17√6/12) =
=10√6-17√6/12) =
=120√6-17√6)/12=
=103√6/12

b)(9/√3-12/√12+14/2√3)-(8√3-8/√27+15/2√3) =
=(9/√3-12/2√3+7/√3)-(8√3-8/3√3+15/2√3) =
=(9√3/3-6√3/3+7√3/3)-(8√3-8√3/9+15√3/6) =
=3√3-2√3+7√3/3-8√3+8√3/9-5√3/2) =
=7√3/3-7√3+8√3/9-5√3/2) =
=42√3-126√3+16√3-45√3)/18 =
=-113√3/18

c)(9/√27-3/√3+2/√12)-(√12-45/√75+48/4√12) =
=(9/3√3-3/√3+2/2√3)-(2√3-45/5√3+48/8√3) =
=3/√3-3/√3+1/√3-2√3+9/√3-6/√3 =
=√3/3-2√3+9√3/3-6√3/3 =
=-2√3+4√3/3 =
=-6√3/3+4√3/3 =
=-2√3/3

d)(5/√2-3/2√2)-(5√2/6+7/3√2+18/√18) =
=(5/√2-3/2√2)-(5√2/6+7/3√2+18/3√2) =
=5√2/2-3√2/4-12√2/6-18√2/6 =
=5√2/2-3√2/4-2√2-3√2 =
=5√2/2-3√2/4-5√2 =
=(10√2-3√2-20√2)/4 =
=-13√2/4