Question

Vă rog! Ofer 25 puncte
Doar ex 5!!!!​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

$\it \sqrt5 > \sqrt3 \Rightarrow \sqrt5-\sqrt3 > 0 \Rightarrow a=|\sqrt5-\sqrt3|=\sqrt5-\sqrt3\\ \\ 3\sqrt5-4\sqrt3=\sqrt{45}-\sqrt{48} < 0 \Rightarrow b=|3\sqrt5-4\sqrt3|=-3\sqrt5+4\sqrt3$

$\it\rule{0.2}{0.2}_{ 3a-b=3(\sqrt5-\sqrt3)-(-3\sqrt5+4\sqrt3)=3\sqrt5-3\sqrt3+3\sqrt5-4\sqrt3=6\sqrt5-7\sqrt3}$