Question

va rog poate cineva sa ma ajute, dau coroana

Answer 1

1.
$( \frac{1}{2}) {}^{7} = \frac{1 {}^{7} }{2 {}^{7} } = \frac{1}{128}$
$( \frac{2}{3} ) {}^{5} = \frac{32}{81}$
$( \frac{4}{9} ) {}^{3} = \frac{64}{729}$
$( \frac{11}{7} ) {}^{3} = \frac{1331}{343}$
$( \frac{5}{4} ) {}^{4} =( ( \frac{5}{4} ) {}^{2}) {}^{2} = ( \frac{25}{16} ) {}^{2} = \frac{625}{256}$
$( \frac{3}{3} ) {}^{2017} = ( \frac{1}{1} ) {}^{2017} = {1}^{2017} = 1$
$( \frac{19}{43} ) {}^{1} = \frac{19}{43}$
$(\frac{2011}{2017} ) {}^{0} = 1$

2.
$( \frac{2}{3} ) {}^{5} \times ( \frac{2}{3} ) {}^{7} = ( \frac{2}{3} ) {}^{5 + 7} = ( \frac{2}{3} ) {}^{12}$
$( \frac{3}{10} ) {}^{3} \times ( \frac{3}{10} ) {}^{10} = ( \frac{3}{10} ) {}^{13}$

$( \frac{11}{5} ) {}^{4} \times ( \frac{11}{5} ) {}^{6} = ( \frac{11}{5} ) {}^{4 + 6} = ( \frac{11}{5} ) {}^{10}$
$( \frac{3}{4} ) {}^{11} \div ( \frac{3}{4} ) {}^{4} = ( \frac{3}{4} ) {}^{11 - 4} = ( \frac{3}{4} ) {}^{7}$
$( \frac{8}{3} ) {}^{9} \div ( \frac{8}{3} ) {}^{8} = ( \frac{8}{3} ) {}^{9 - 8} = ( \frac{8}{3} ) {}^{1} = \frac{8}{3}$
$( \frac{13}{17} ) {}^{22} \div ( \frac{13}{17} ) {}^{20} = ( \frac{13}{17} ) {}^{22 - 20} = ( \frac{13}{17} ) {}^{2}$
$(( \frac{2}{15} ) {}^{5} ) {}^{11} = ( \frac{2}{15} ) {}^{55}$
$(( \frac{14}{27} ) {}^{6} ) {}^{4} = ( \frac{14}{27} ) {}^{24}$

$(( \frac{3}{100} ) {}^{0} ) {}^{2017} = {1}^{2017}$