Question

Va rog, problema 18!!

Answer 1

pV=nRT => n=pV/RT=3*196,8/0,082*300=24 moli CH4

m CH4=24*16=384g

x..........x..............x........x
CH4 + Cl2 => CH3Cl + HCl
y..........2y.............y..........2y
CH4 + 2Cl2 => CH2Cl2 + 2HCl
z...........3z...........z...........3z
CH4 + 3Cl2 => CHCl3 + 3HCl
w.........4w.........w.......4w
CH4 + 4Cl2 => CCl4 + 4HCl

x/y=1/2 => y=2x => y=6 moli

x/z=1/3 => z=3x => z=9 moli

x/w=1/2 => w=2x => w=6 moli

x+2x+3x+2x=24 => 8x=24 =>x=3 moli

a) m CHCl3=9*119,5=1075,5g 

b) w= 6 moli CCl4

m CCl4=6*154=924g

c) x+2y+3z+4w=3+12+27+24=66 moli HCl

nHCl=nNaOH=66 moli 

md NaOH=66*40=2640g

C=md/ms*100=>ms=md*100/C=264000/20=13200g=13,2kg NaOH

d) n Cl2=66 moli

110/100*66=72,6 moli Cl2

V Cl2=22,4*72,6=1626,24L Cl2

e) m amestec = 3*50,5+6*85+9*119,5+6*154=2661g

%CH3Cl=mCH3Cl/m amestec*100 = 151,5/2661*100=5,693

%CH2Cl2=

%CHCl3=

%CCl4=