Question

va rog problema 2............ raportez pe cei care isi bat joc!

Answer 1

AB=10cm
AC=10√3cm
m<B)=60 grade
ducem inaltimeadin A pe BC in punctul D
ΔADB dreptunghic in pct.Dsi unghiu B=60grade=>BD=AB/2
BD=10cm/2=5cm
AD² =AB² - BD²
AD²=10²-5²
AD²=100-25=75
AD=√75=AD=5√3
ΔADC dreptunghic in d
AC²=AD²+DC²
(10√3)²- (5√3)²=DC²
DC²=300-75
DC²=225
DC=15 cm
BC=BD+DC
BC=5+15 cm=20cm
b)conform teorema lui pitagora BC²=AB²+AC²=. CA TRIUNGHIUL ESTE DREPTUNGHIC
(20CM)²=(10CM)²+(10√3CM)²
400CM²=100CM²+300CM²