Question

va rog raspuns rapid. Efectuati calculele :
a) (√5-3)²+3√5(2-√5)
b) 2(√2+3)²-4√2(3-√2)
c) 3(√3-1)²-√3(√3-6)-(√11-√2)(√11-√2)(√11+√2)
Multumesc anticipat

Answer 1

a) (√5-3)²+3√5(2-√5)
= 5-6√5+9+6√5-15
=-1
b) 2(√2+3)²-4√2(3-√2)
= 2(2+6√2+9)-12√2+8
=4+12√2+18-12√2+8
= 30
c) 3(√3-1)²-√3(√3-6)-(√11-√2)(√11-√2)(√11+√2)
= 3(3-2√3+1)-3+√18-√11+√2(11-2)
= 9-6√3+3-3+√18-√11+11√2-√2
= 20-6√3+3√2-√11+11√2-√2
= 20-6√3-√11+13√2

Answer 2

a)
$5 - 6 \sqrt{5} + 9+ 6 \sqrt{5} - 15 = 14 - 15 = - 1$
b)