Question

Va rog repede 1 și 3​

Answer 1

3)

$\it x+4 >\dfrac{2x+10}{3}>x+2|_{\cdot3} \Rightarrow 3x+12>2x+10>3x+6|_{-3x} \Rightarrow\\ \\ \\ \Rightarrow 12>-x+10>6|_{-10} \Rightarrow 2>-x>-4|_{\cdot(-1)} \Rightarrow -2<x<4\ \ \ \ (*)\\ \\ \\ x\in\mathbb{Z} \stackrel{(*)}{\Longrightarrow} A=\{-1,\ 0,\ 1,\ 2,\ 3\}$