Question

va rog repede........​

Answer 1

$\displaystyle \frac{1,(6)}{1,25-0,2(7)} =\frac{4}{x} \Rightarrow \frac{\cfrac{16-1}{9} }{\cfrac{125}{100} -\cfrac{27-2}{90} } =\frac{4}{x} \Rightarrow \frac{\cfrac{15}{9} }{\cfrac{125}{100} -\cfrac{25}{90} }=\frac{4}{x} \Rightarrow \\\\ \Rightarrow \frac{\cfrac{5}{3} }{\cfrac{5}{4} -\cfrac{5}{18} }=\frac{4}{x} \Rightarrow \frac{\cfrac{5}{3} }{\cfrac{45-10}{36} }=\frac{4}{x} \Rightarrow \frac{\cfrac{5}{3} }{\cfrac{35}{36} } =\frac{4}{x} \Rightarrow \frac{5}{3}\cdot\frac{36}{35} =\frac{4}{x} \Rightarrow$

$\displaystyle \Rightarrow \frac{12}{7} =\frac{4}{x} \Rightarrow 12x=4 \cdot 7 \Rightarrow 12x=28 \Rightarrow x=\frac{28}{12} \Rightarrow x=\frac{7}{3}$