Question

Va rog, repede!
Dau coroana ​

Answer 1

Răspuns:

f) $x^{3} (x+3)+8(x+3)=(x+3)(x^{3} +1)=(x+3)(x+1)(x^{2} -x+1)$

g) $x^{3} (x-2)-27(x-2)=(x-2)(x^{3}-27)=(x-2)(x-3)(x^{2} +3x+9)$

h)

$x^{4}(x^{2} +7)-4(x^{2} +7)=(x^{2} +7)(x^{4}-4)=( x^{2} +7)(x^{2} -4)(x^{2} +4)=(x-2)(x+2)( x^{2} +7)(x^{2} +4)$

i) $x^{4} (x^{2} -5)-9(x^{2} -5)=(x^{4} -9)(x^{2} -5)=(x^{2} +3)(x^{2} -3)(x -\sqrt{5} )(x +\sqrt{5} )=(x^{2} +3)(x-\sqrt{3})(x+\sqrt{3)}(x -\sqrt{5} )(x +\sqrt{5} )$