Question

va rog repede dau coroana​

Answer 1

Salut!

a) x + y + z = 24 ( 1 )

( x; y; z ) dp ( 3; 4; 5 )

$\frac{x}{3} = \frac{y}{4} = \frac{z}{5} = k$

==> x = 3k

y = 4k

z = 5k

( 1 )

====> 3k + 4k + 5k = 24

12k = 24

k = 24 : 12

k = 2 ✓

x = 3 • 2

x = 6 ✓

y = 4 • 2

y = 8 ✓

z = 5 • 2

z = 10 ✓

b) x + y + z = 36 ( 1 )

( x; y; z ) dp ( 3; 4; 5 )

$\frac{x}{3} = \frac{x}{4} = \frac{z}{5} = k$

==> x = 3k

y = 4k

z = 5k

( 1 )

====> 3k + 4k + 5k = 36

12k = 36

k = 36 : 12

k = 3 ✓

x = 3 • 3

x = 9 ✓

y = 4 • 3

y = 12 ✓

z = 5 • 3

z = 15 ✓

c) x + y + z = 132 ( 1 )

( x; y; z ) dp ( 3; 4; 5 )

$\frac{x}{3} = \frac{y}{4} = \frac{z}{5} = k$

==> x = 3k

y = 4k

z = 5k

( 1 )

====> 3k + 4k + 5k = 132

12k = 132

k = 132 : 12

k = 11 ✓

x = 3 • 11

x = 33 ✓

y = 4 • 11

y = 44 ✓

z = 5 • 11

z = 55 ✓