Matematică, întrebare adresată de SkuupLz, 8 ani în urmă

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10)a)

 \frac{1}{2}  -  \frac{1}{3} =  \frac{1}{6}

 \frac{1}{2}  -  \frac{1}{6}  =  \frac{1}{3}

 \frac{1}{3} -  \frac{1}{6}   =  \frac{1}{6}

 \frac{1}{2}  - ( \frac{1}{3}  +  \frac{1}{6} ) = 0

b)

1 \frac{1}{5}  -  \frac{3}{4}  =  \frac{9}{20}

1 \frac{1}{5}  -  \frac{1}{5}  = 1

 \frac{3}{4}  -  \frac{1}{5}  =   \frac{11}{20}

1 \frac{1}{5}  - ( \frac{3}{4}  +   \frac{1}{5} ) =  \frac{1}{4}

c)

7 {1}^{2}  - 3 \frac{1}{4}  = 4 \frac{1}{4}

7  \frac{1}{2}  - 1 \frac{2}{5} = 6 \frac{1}{10}

3 \frac{1}{4}  - 1 \frac{2}{5}  =  \frac{37}{20}

7 \frac{1}{2}  - (3 \frac{1}{4} + 1 \frac{2}{5}  ) =  \frac{57}{20}

d)

2 \frac{3}{10}  - 1 \frac{2}{10}

2 \frac{3}{10}  -  \frac{2}{5}  =  \frac{19}{10}

1 \frac{2}{5}  -   \frac{2}{5}  = 1

2 \frac{3}{10}  - (1 \frac{2}{5}  +  \frac{2}{5} ) =  \frac{1}{2}

e)

3 \frac{3}{8}  - 2 \frac{1}{10}  = 1 \frac{11}{40}

3 \frac{3}{8}  - 1 \frac{1}{4}  = 2 \frac{1}{8}

2 \frac{1}{10}  - 1 \frac{1}{4}  =  \frac{17}{20}

3 \frac{3}{8}  - (2 \frac{1}{10}  + 1 \frac{1}{4} ) =  \frac{1}{40}

f)

4 \frac{9}{10}  - 2  \frac{4}{5 }  = 2 \frac{1}{10}

4 \frac{9}{10}  - 1 \frac{1}{2}  = 3 \frac{2}{5}

2 \frac{4}{5}  - 1 \frac{1}{2}  = 1 \frac{3}{10}

4 \frac{9}{10}  - (2 \frac{4}{5}  + 1 \frac{1}{2} ) =  \frac{3}{5}

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