Question

Va rog repedeee!!!!!!!!!​

Answer 1

Notam tgA = x

ctg A = 1/tg A = 1/x

3(x+1/x) = 4√3

3x+3/x = 4√3 | *x

3x²+3 = 4√3x

3x²-4√3x+3 = 0

Δ = 48 - 36 = 12

x1 = (4√3-2√3)/6 = 2√3 / 6 = √3 / 3

x2 = (4√3+2√3)/6 = 6√3 / 6 = √3

tg A = √3 / 3 ⇒ m(∡A) = 30°

tg A = √3 ⇒ m(∡A) = 60°

m(∡A) ∈ {30°, 60°}