Question

Vă rog repedeeee!!!Dau coroana!!!

Answer 1

vezi rezolvarea in foto

Answer 2

→ intoduc intregii in fractie

5 intregi si 1 / 8 = ( 5 x 8 + 1 ) / 8 = 41 / 8

[ 3 ( x + 1 / 5 ) · 7 / 2 - 4 ] · 3 + 4 = 41 / 8

[ 3 ( x + 1 / 5 ) · 7 / 2 - 4 ] · 3 = 41 / 8 - 4 = ( 41 - 32 ) / 8 = 9 / 8

3 ( x + 1 / 5 ) · 7 / 2 - 4 = 9 / 8 : 3 = 9 / 8 × 1 / 3 = 3 / 8

3 ( x + 1 / 5 ) · 7 / 2 = 3 / 8 + 4 = ( 3 + 32 ) / 8 = 35 / 8

3 ( x + 1 / 5 ) = 35 / 8 : 7 / 2 = 35 / 8 · 2 / 7 = 5 / 4

x + 1 / 5 = 5 / 4 : 3 = 5 / 4 · 1 / 3 = 5 / 12

x = 5 / 12 - 1 / 5

x = ( 25 - 12 ) / 60 = 13 / 60 → am folosit metoda mersului invers

x = 13 / 60