Question

Va rog rezolvare completa!!​

Answer 1

AB||CD => (Din teorema fundamentala a asemanarii) CD/AB = MD/AM = MC/MB = 4/6 = 2/3

$= > \frac{aria \: tr. \: mdc}{aria \: tr. \: mab} = {( \frac{2}{3} )}^{2} = \frac{4}{9} \\ \frac{aria \: tr. \: mdc}{aria \: tr. \: mdc + 50} = \frac{4}{9} \\ 9 \times a.tr.mdc = 4 (a.tr.mdc + 50) \\ 9 \times a.tr.mdc = 4 \times a.tr.mdc + 200 \\ 5 \times a.tr.mdc = 200 \\ aria \: tr.mdc = 40 \: {m}^{2}$

Răspuns: b) 40m2