Question

Va rog rezolvați asta
x=(-3)×(+7)-[(-18):(+3)-(+24):(-6)+(-32):(-4)]×(-11+9)
y=[(-7)×(+4)-(-8)×(+3)-(-6)×(-2)]:(-6+8)
calculati n=x+y.

Answer 1

$x=$

$\left(-3\right)\times \left(7\right)-\left[\left(-18\right)\div \left(3\right)-\left(24\right)\div \left(-6\right)+\left(-32\right)\div \left(-4\right)\right]\times \left(-11+9\right) =$

$\left(-3\right)\times \left7\right-\left[-6-\left24\right\div \left(-6\right)+\left(-32\right)\div \left(-4\right)]\times \left(-11+9\right) =$

$\left(-3\right)\times \left7\right-\left[-6-\left(-4\right)+\left(-32\right)\div \left(-4\right)]\times \left(-11+9\right) =$

$\left(-3\right)\times \left7\right-\left[-6-\left(-4\right)+8]\times \left(-11+9\right) =$

$\left(-3\right)\times \left7\right-6\times \left(-11+9\right) =$

$\left(-3\right)\times \left(7\right)-6\times \left(-2\right) =$

$-21-6\times \left(-2\right) =$

$-21-\left(-12\right) = -9$

$y=$

$\left[\left(-7\right)\times \:4-\left(-8\right)\times \:3-\left(-6\right)\times \left(-2\right)\right]\div \left(-6+8\right) =$

$\left(-7\right)\times \:4-\left(-8\right)\times \:3-\left(-6\right)\times \left(-2\right) \div \left(-6+8\right) =$

$-28-\left(-8\right)\times \:3-\left(-6\right)\times \left(-2\right) \div \left(-6+8\right)=$

$-28-\left(-24\right)-\left(-6\right)\times \left(-2\right) \div \left(-6+8\right)=$

$-28-\left(-24\right)-12 \div \left(-6+8\right)=$

$-16\div \left(-6+8\right)$

$-16\div \:2 = -8$

$n=x+y$

$n = -9 +(-8)$

$n = -9 -8$

$n = 17$